Some basic questions concerning Stepper motor with geared head/geared box.
What is the meaning the reduction 1:56 (1/56) or 1:100 (1/100) or 18/1? According to some charts: How can i know (calculate) the RPM from the reduction ratio? Why there are more reduction for the same Holding torqoue (eg.: J57HB56-03 Holding torque = 0,9 Nm but the reduction can be 1:3 or 1:5)? Does it have affect on the motor life long if i use great reduction (1:100) to increase the torqoue from smal stepper motor? I mean that motor life wil be shorter. First thing first, nema 23 geared reduction of 1:56 means that for every 56 turns the end shaft of the gear box will do 1 turn. The more gear reduction you have the slower the motor will turn but with higher torque. When using a gearbox you are trading motor speed for torque. It is quite simple calculating the RPM from the reduction ratio. Assuming you motor spins at 500 RPM and your gear is 1:46 then the motor with gear will spin at 500/46 = 10.86RPM. In stepper motors it is not so simple to determine what is the motor top speed as it depends on the voltage you use, the driver (better drivers can drive the motor faster) and the quality of the motor. It is also important to know that stepper motors have different torques in different RPMS and "Usually" (but not always) the slower you go the more torque you have. Gearbox does not affect gear reduction stepper motor life no mater what is the gear ratio. Each gearbox has a torque limit and applying a torque higher than the maximum recommended torque will damage the gearbox. 2 Methods To Design Stepper Motor Control Circuit
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